lreplace - Replace elements in a list with new elements


lreplace list first last ?element element ...?


lreplace returns a new list formed by replacing one or more elements of list with the element arguments. first and last specify the first and last index of the range of elements to replace. 0 refers to the first element of the list, and end (or any abbreviation of it) may be used to refer to the last element of the list. If list is empty, then first and last are ignored. If first is less than zero, it is considered to refer to the first element of the list. For non-empty lists, the element indicated by first must exist. If last is less than zero but greater than first, then any specified elements will be prepended to the list. If last is less than first then no elements are deleted; the new elements are simply inserted before first. The element arguments specify zero or more new arguments to be added to the list in place of those that were deleted. Each element argument will become a separate element of the list. If no element arguments are specified, then the elements between first and last are simply deleted. If list is empty, any element arguments are added to the end of the list.


Replacing an element of a list with another:
% lreplace {a b c d e} 1 1 foo
a foo c d e

Replacing two elements of a list with three:

% lreplace {a b c d e} 1 2 three more elements
a three more elements d e

Deleting the last element from a list in a variable:

% set var {a b c d e}
a b c d e
% set var [lreplace $var end end]
a b c d


list, lappend, lindex, linsert, llength, lsearch, lset, lrange, lsort


element, list, replace
Copyright © 1993 The Regents of the University of California.
Copyright © 1994-1996 Sun Microsystems, Inc.
Copyright © 2001 Kevin B. Kenny. All rights reserved.
Copyright © 1995-1997 Roger E. Critchlow Jr.